Question

Question 20(i)
Two dice are thrown simultaneously. What is the probability that the sum of the numbers appearing on the dice is 7?

Answer 1

Two dice are thrown simultaneously.
So, the total number of possible outcomes = 36.
Sum of the numbers appearing on the dice is 7.
So, the possible ways are (1,6), (2,5), (3,4), (4,3), (5,2) and (6,1).
Number of possible ways = 6
$\therefore$ Required probability $=\frac{6}{36}=\frac{1}{6}$