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Algebraic Identities

i Using x+ax+...

Question

Question 8(i)
Using $(x + a) (x + b) = x^{2} + (a + b) x + a b$ , find
$103 \times 104$

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Solution

$103 \times 104 = (100 + 3) \times (100 + 4)$
$= (100)^{2} + (3 + 4) \times 100 + 3 \times 4$
$[U s i n g i d e n t i t y (x + a) (x + b) = x^{2} + (a + b) x + a b]$
$= 10000 + 7 \times 100 + 12$
$= 10000 + 700 + 12 = 10712$

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Similar questions

Q. Question 8(i)
Using

(x + a) (x + b) = x^{2} + (a + b) x + a b

103 \times 104

Question 8(iii)
Using $(x + a) (x + b) = x^{2} + (a + b) x + a b$ , find
$103 \times 98$

Q. Question 8(ii)
Using

(x + a) (x + b) = x^{2} + (a + b) x + a b

5.1 \times 5.2

(x + a) (x + b) = x^{2} + (a + b) x + a b,

103 \times 104

Q. Using (x+a)(x+b)=

x^{2}

+(a+b)x+ab,find the value of

(a) 103 \times 104

(b) 103 \times 98

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Algebraic Identities

Standard VIII Mathematics