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Ionic Bond

I. When iron ...

Question

$I$ . When iron reacts with oxygen an iron oxide compound with the formula of ${F e}_{2} O_{3}$ can be formed.
$I I$ . Iron atoms form cations with a charge of $+ 3$ by losing $3$ electrons and oxygen atoms gain $2$ electrons to form an anion with a $- 2$ charge.

Statement

I

is true, Statement

I I

is true and is a correct explanation of the phenomena described in

I

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Statement

I

is true, Statement

I I

is false

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Statement

I

is false, Statement

I I

is true

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Statement

I

is false, Statement

I I

is false

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Solution

The correct option is A Statement $I$ is true, Statement $I I$ is true and is a correct explanation of the phenomena described in $I$
$4 F e (s) + 3 O_{2} (g) \to 2 F e_{2} O_{3} (s)$
Fe looses 3 electrons and gains +3 charge and oxygen gains 2 electrons and becomes -2 charge.
$F e^{0} (s) \to F e^{3 +} + 3 e^{-}$ (1)
$O^{0} (g) + 2 e^{-} \to 2 O^{2 -}$ (2)
$(1) \times 4, (2) \times 3$
$4 F e (s) \to 4 F e^{3 +} + 12 e^{-}$
$3 O (g) + 12 e^{-} \to 6 O^{2 -}$
$4 F e (s) + 3 O_{2} (g) \to 4 F e^{3 +} + 6 O^{2 -} \to F e_{2} O_{3} (s)$

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I. When iron reacts with oxygen an iron oxide compound with the formula of Fe2O3 can be formed.II. Iron atoms form cations with a charge of +3 by losing 3 electrons and oxygen atoms gain 2 electrons to form an anion with a −2 charge.

$I$ . When iron reacts with oxygen an iron oxide compound with the formula of ${F e}_{2} O_{3}$ can be formed.
$I I$ . Iron atoms form cations with a charge of $+ 3$ by losing $3$ electrons and oxygen atoms gain $2$ electrons to form an anion with a $- 2$ charge.