I- x2-10 x-16 -x2-12 x-24-2 - 3II- y 2- y -20-0A- if xyD- if x - yE- if x-y or relation cannot be established between -x- and -y-

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I. x2-10 x+16...

Question

I. $(x^{2} - 10 x + 16) / (x^{2} - 12 x + 24) = 2 / 3$
II. $y^{2} - y - 20 = 0$

if x > y

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if x < y

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if x $\geq$ y

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if x $\leq$ y

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if x = y or relation cannot be established between 'x' and 'y'.

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\frac{x^{2} - 10 x + 16}{x^{2} - 12 x + 24} = \frac{2}{3}

y^{2} - y - 20 = 0

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