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Question

Identify the complex which are expected to be colourless.


A
[Ti(NO3)4]0
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B
[Cu(NCCH3)4]+
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C
[Cr(NH3)6]Cl3
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D
K3VF6
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Solution

The correct options are
A $$[Ti(NO_3)_4]^{0}$$
B $$[Cu(NCCH_3)_4]^{+}$$
The complexes $$[Ti(NO_3)_4]^{0}$$ and $$[Cu(NCCH_3)_4]^{+}$$ are expected to be colourless.
(A) In $$[Ti(NO_3)_4]^{0}$$, Ti(IV) ion with electronic configuration $$[Ar] 3d^04s^0$$ has 0 unpaired electron. Hence, it is expected to be colourless as no d-d transition is possible.
(B) In $$[Cu(NCCH_3)_4]^{+}$$, Cu(I) ion with electronic configuration $$[Ar] 3d^{10}4s^0$$ has 0 unpaired electrons and is expected to be colourless as no d-d transition is possible.
(C) In $$[Cr(NH_3)_6]Cl_3$$, Cr(III) ion with electronic configuration $$[Ar]3d^34s^0$$ contains 3 unpaired electrons and is expected to have violet color due to d-d transitions.
(D) In $$K_3VF_6$$, V(III) ion with electronic configuration $$3d^24s^0$$ has 2 unpaired electrons and is expected to have green colour due to d-d transition.

Chemistry

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