Identify the correct pathway to convert propanoic acid to ethylamine. The reagent represented by $A, B$ and $C$ are: $C H_{3} C H_{2} C O O H A \to X B \to Y C \to C H_{3} C H_{2} N H_{2}$

A = C a (O H)_{2}, B = H e a t, C = P t / H_{2}

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A = S O C l_{2}, B = N H_{3}, C = B r_{2} / K O H

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A = H N O_{2}, B = P + I_{2}, C = L i A l H_{4}

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A = H C N, B = N H_{3}, C = B r_{2} / K O H

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Solution

The correct option is B $A = S O C l_{2}, B = N H_{3}, C = B r_{2} / K O H$
$C H_{3} C H_{2} C O O H S O C l_{2} - --- \to (A) C H_{3} C H_{2} C O C l (X) N H_{3} - -- \to (B) C H_{3} C H_{2} N H_{2} B r_{2} / K O H \leftarrow ----- - (C) C H_{3} C H_{2} C O N H_{2} (Y)$

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Similar questions

C H_{3} C H_{2} C O O H A \to X B \to Y C \to C H_{3} C H_{2} N H_{2}

N H_{3}

B r_{2}

N H_{3}

K O H

B r_{2}

C H_{3} C H_{2} N H_{2}

Ph - C \equiv N H_{3} O^{+} - --------- \to Partial Hydrolysis (A) {Br}_{2} + KOH - ---- \to (B)

2 N a C l + C a C O_{3} \to N a_{2} C O_{3} + C a C l_{2}

C a C O_{3} Δ - \to [A] + [B]

N a C l + N H_{3} + [B] + H_{2} O \to [C] + [D]

2 [C] \to N a_{2} C O_{3} + H_{2} O + [B]

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