Identify the correct statement regarding the following chemical reaction.
$2 H I (a q) + C l_{2} (a q) ⟶ I_{2} (s) + 2 H C l (a q)$

Iodine in HI is reduced and chloride is oxidized.

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Iodine in HI is oxidised and chloride is reduced.

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Both Iodine in HI and chloride are reduced.

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Both Iodine in HI and chloride are oxidized.

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Solution

The correct option is B Iodine in HI is oxidised and chloride is reduced.
Change in oxidation numbers are given below:
$I \Rightarrow - 1$ to $0$
$C l \Rightarrow 0$ to $- 1$
$H \Rightarrow + 1$ to $+ 1$ (no change)
Hence, iodine in HI is oxidised and chloride is reduced.

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Identify the correct statement regarding the following chemical reaction.2HI(aq)+Cl2(aq)⟶I2(s)+2HCl(aq)

The correct option is B Iodine in HI is oxidised and chloride is reduced.Change in oxidation numbers are given below:I⇒−1 to 0Cl⇒0 to −1H⇒+1 to +1 (no change)Hence, iodine in HI is oxidised and chloride is reduced.

Identify the correct statement regarding the following chemical reaction.
$2 H I (a q) + C l_{2} (a q) ⟶ I_{2} (s) + 2 H C l (a q)$

The correct option is B Iodine in HI is oxidised and chloride is reduced.
Change in oxidation numbers are given below:
$I \Rightarrow - 1$ to $0$
$C l \Rightarrow 0$ to $- 1$
$H \Rightarrow + 1$ to $+ 1$ (no change)
Hence, iodine in HI is oxidised and chloride is reduced.