Identify the gas evolved when potassium sulphite is treated with dilute hydrochloric acid.

S_{2}

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O_{2}

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{S O}_{2}

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None of these

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Solution

The correct option is C ${S O}_{2}$
When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.

$K_{2} {S O}_{3} + H C l \to K C l + H_{2} O + {S O}_{2}$

Hence, option C is correct.

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Similar questions

Q. Identify the gas evolved in the following reactions when: Potassium suphite is treated with dilute hydrochloric acid.

Q. Potassium sulphite on reacting with hydrochloric acid released _________ gas.

(C l_{2}, S O_{2}, H_{2} S)

Q. Identify the gas evolved and give the chemical test in each of the following case :
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Q. Name the gas evolved when dilute hydrochloric acid is added to: [2 MARKS]
a) Calcium carbonate
b) Sodium sulphite

When sodium sulphite reacts with the dilute hydrochloric acid, salt X, water and gas Y is formed. Gas X decolourised pink potassium permanganate solution. Gas X is:

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Identify the gas evolved when potassium sulphite is treated with dilute hydrochloric acid.

The correct option is C SO2When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.K2SO3+HCl→KCl+H2O+SO2Hence, option C is correct.

The correct option is C ${S O}_{2}$
When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.

$K_{2} {S O}_{3} + H C l \to K C l + H_{2} O + {S O}_{2}$

Hence, option C is correct.