Identify the oxidant and the reductant in the following reaction respectively-2 KMnO 4-10 KCl -8 H 2 SO 4- 2 MnSO 4-6 K 2 SO 4-8 H 2 O -5 Cl 2A- KMnO 4- KClB- KMnO 4- H 2 SO 4C- MnSO 4- KM nO 4D- KCl - KMnO 4

The correct option is A KMnO_4 & KClThe given redox reaction is (+7)2KMnO_4+ ( 1)10KCl + 8H_2SO_4 → nbsp;(+2)2MnSO_4 + 6K_2SO_4 + 8H_2O + (0)Cl_2. Reduct ...

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Byju's Answer

Standard XII

Chemistry

Redox Reactions

Identify the ...

Question

Identify the oxidant and the reductant in the following reaction respectively:
$2 K M n O_{4} + 10 K C l + 8 H_{2} S O_{4} \to 2 M n S O_{4} + 6 K_{2} S O_{4} + 8 H_{2} O + 5 C l_{2}$

K M n O_{4}

&

K C l

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K M n O_{4}

&

H_{2} S O_{4}

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M n S O_{4}

&

K M n O_{4}

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K C l

&

K M n O_{4}

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Solution

The correct option is A $K M n O_{4}$ $&$ $K C l$
The given redox reaction is
$(+ 7) 2 K M n O_{4} + (- 1) 10 K C l + 8 H_{2} S O_{4} \to (+ 2) 2 M n S O_{4} + 6 K_{2} S O_{4} + 8 H_{2} O + (0) C l_{2} .$
$Reduction half reaction$
A species which gains electron in a redox reaction is called as oxidising agent/oxidant.
$(+ 7) 2 K M n O_{4} (oxidant) \to (+ 2) 2 M n S O_{4}$ .
Here $K M n O_{4}$ is gaining electron so it is an oxidant.

$Oxidation half reaction$
A species which looses electron in a redox reaction is called as reducing agent/reductant.
$(- 1) 10 K C l (reductant) \to (0) 5 C l_{2}$ .
Here KCl is losing reagent so it is a reductant.

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Similar questions

Q. Identify the oxidant and the reductant in the following reaction respectively:

2 K M n O_{4} + 10 K C l + 8 H_{2} S O_{4} \to 2 M n S O_{4} + 6 K_{2} S O_{4} + 8 H_{2} O + 5 C l_{2}

Q. Identify the correctly balanced redox reaction using ion-electron method.

F e S O_{4} + K M n O_{4} + H_{2} S O_{4} \to F e_{2} (S O_{4})_{3} + M n S O_{4} + H_{2} O + K_{2} S O_{4}

Q. Identify X in the given reaction.

{CH}_{3} {CH}_{2} OH (aq) X \to {CH}_{2} = {CH}_{2} (g) + H_{2} O(l)

Q. The reaction between

H_{2} O_{2}

and

K M n O_{4}

2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} O_{2} \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O + 5 O_{2}

In a reaction excess of

H_{2} O_{2}

is added to 0.1 mole of acidified

K M n O_{4}

solution. Then the STP volume of

O_{2}

liberated is:

Q. The reaction, is an example of reaction of:

2 M n S O_{4} + 2 K M n O_{4} + 8 H_{2} S O_{4} \to 2 M n S O_{4} + 5 F e_{2} (S O_{4})_{3} + K_{2} S O_{4} + 8 H_{2} O

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Redox Reactions

Standard XII Chemistry

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Identify the oxidant and the reductant in the following reaction respectively: 2KMnO4+10KCl+8H2SO4→2MnSO4+6K2SO4+8H2O+5Cl2

Identify the oxidant and the reductant in the following reaction respectively:
$2 K M n O_{4} + 10 K C l + 8 H_{2} S O_{4} \to 2 M n S O_{4} + 6 K_{2} S O_{4} + 8 H_{2} O + 5 C l_{2}$