Identify the oxidized and reduced substances in the following reactions.
2Al(s) + 6HCl(aq) $\to$ 2AlCl₃(aq) +3H₂(g)

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Solution

A substance is oxidized when it loses electrons.
A substance is reduced when it gains electrons
In the given reaction, aluminum(Al) loses electrons and those electrons are gained by chlorine(Cl).
Therefore, the substance oxidized is aluminum(Al) and the reduced one is chlorine(Cl).
Here, aluminum is a reducing agent and HCl is the oxidizing agent.

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Identify the oxidized and reduced substances in the following reactions.

H₂(g) + Cl₂(g) $\to$ 2HCl(g)

2 A l (s) + 6 H C l (a q) \to

2 A l H_{3} (a q) + 3 C l_{2} (g)

A l_{2} O_{3} (a q) + 3 H_{2} (g)

2 A l (O H)_{3} (a q) + 3 C l_{2} (g)

2 A l C l_{3} (a q) + 3 H_{2} (g)

$2 Al (s) + 6 HCl (aq) \to$

2 A l (s) + 6 H C l (a q) \to 2 A l^{3 +} (a q .) + 6 C l^{-} (a q .) + 3 H_{2} (g)

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