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Question

Identify the reaction, give example with equation.
$$(I)$$ products become hot/warm
$$(II)$$ product is in soluble
$$(III)$$ product cools down.


Solution

(i) Product becomes hot/warm:-
 Any exothermic reaction, i.e. reactions which involve release of heat make the product hot/warm.
 Eg:- All combustion reactions, A neutralization reaction etc.
$$ NaOH(aq)+HCl(aq)\longrightarrow NaCl(aq)+{ H }_{ 2 }O(l)+Heat$$
 sodium$$\quad \quad \quad \quad $$Hydro$$ \quad \quad \quad$$ sodium$$ \quad \quad$$ water
 hydroxide$$\quad \quad$$ chloro acid$$\quad \quad $$cloride
 $$\Delta G=-52kL/mol$$
 (ii) Product is in soluble:-
 Technical reaction in which the product remain as a precipitate which is soluble.
 $$ 2AgN{ O }_{ 3 }(aq)\quad +\quad Mg{ Br }_{ 2 }\quad \longrightarrow \quad 2AgBr(s)\quad +\quad Mg{ ({ NO }_{ 3 }) }_{ 2 }(aq)$$
 silver nitrate               magnesium                 silver              Magnesium
                                  Bromide                        Bromide           Nitrate
In the above reaction silver Bromide $$ (AgBr)$$ remains as a precipitate as it is insoluble in aquas magnesium nitrate.
(iii) Product cools down:-
 Any endothermic reaction i.e, reactions which involve absorption of energy from the surroundings eventually cools down the products.
 Eg:-
$$ N{ H }_{ 4 }Cl(s)\quad +{ \quad H }_{ 2 }O(l)\quad \longrightarrow \quad { NH }_{ 4 }Cl(aq)\quad -\quad Heat$$
 Ammonium          Water                        aqeous
 cloride                                                  Ammonium
                                                                cloride

Chemistry

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