Identify the reaction in which the heat liberated corresponds to the heat of formation $(△ H)$ :

C (d i a m o n d) + O_{2} (g) \to {C O}_{2} (g) + h e a t

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{2 H}_{2} (g) + O_{2} (g) \to 2 H_{2} O (g) + h e a t

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C (d i a m o n d) + 2 H_{2} (g) \to {C H}_{4} (g) + h e a t

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S (r h o m b i c) + O_{2} (g) \to {S O}_{2} (g) + h e a t

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Solution

The correct option is A $C (d i a m o n d) + O_{2} (g) \to {C O}_{2} (g) + h e a t$
The heat of reaction resulting from the formation of a compound by direct union of its elements is called Heat of Formation.
So Option A is correct

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Similar questions

C_{(d i a m o n d)} + O_{2} (g) \to C O_{2} (g) △ H = - 94.5 K c a l

C_{(g r a p h i t e)} + O_{2} (g) \to C O_{2} (g) △ H = - 94.0 K c a l

C_{(s)} + O_{2 (g)} \to C O_{2 (g)};

Δ H = - 394 k J

2 H_{2 (g)} + O_{2 (g)} \to 2 H_{2} O_{(l)};

Δ H = - 568 k J

C H_{4 (g)} + 2 O_{2 (g)} \to C O_{2 (g)} + 2 H_{2} O_{(l)};

Δ H = - 394 k J

C H_{4}

C (d i a m o n d, s) + O_{2} (g) \to C O_{2} (g); △ H = - 94.3 k c a l

C (g r a p h i t e, s) + O_{2} (g) \to C O_{2} (g); △ H = - 97.6 k c a l

C (d i a m o n d, s) \to C (g r a p h i t e, s)

2 H_{2} (g) + O_{2} (g) ⟶ 2 H_{2} O (g)

Δ H = - 573.2 k J

(Δ H)

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