Question

Identify the solutions for the given equation 4x + y = 16.

• A. (0, 16)
• B. (4, 0)
• C. (0, 8)
• D. (3, 2)

Answer 1

Answer: (A), (B)

(4, 0)

The given equation is 4x + y = 16.

(i) (0, 16)
Putting x = 0 and y = 16 in the given equation:
LHS = (4 $\times$ 0) + 16 = 16 (RHS)
Thus, (0, 16) is a solution of the given equation.

(ii) (4, 0)
Putting x = 4 and y = 0 in the given equation:
LHS = (4 $\times$ 4) + 0 = 16 (RHS)
Thus, (4, 0) is a solution of the given equation.

(iii) (0, 8)
If we put x = 0 and y = 8 in the given equation:
$4\left(0\right)+8=8\ne 16\left(RHS\right)$, and thus (0, 8) is not a soltuion of the given equation.

(iv) (3, 2)
Similarly, putting x = 3 and y = 2 in the given equation, we get $4\left(3\right)+2=14\ne 16\left(RHS\right)$, and thus (3, 2) is also not a soltuion of the given equation.