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B
(CH3)2CHCH2Br, CH3CH=CHCH3
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C
(CH3)2CHBrCH2Br, (CH3)2C=CH2
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D
(CH3)2CHCHBr2, (CH3)2C=CH2
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Solution
The correct option is D(CH3)2CHBrCH2Br, (CH3)2C=CH2 CH3−Br|C|CH3−Br|CH2Zn−−−−−→−ZnBr2CH3−C|CH3=CH2O3−−−−−→Zn+H2O(CH3)2C=O+HCHO
In presence of Zn the 2-methyl-1,2-dibromo propane undergoes dehalogenation reaction to form isobutylene. The isobutylene on reaction with ozone it undergoes ozonolysis to form ozonide which on hydrolysis forms corresponding ketone as a product.
Hence the option C is correct and the compounds given in option C are X and Y respectively.