If 0-13- p 2 -13- then p-

The correct option is A 0.1 0.13 ÷ p^2 =13 ∴ 0.13 ×1/p^2 = 13 ⇒ 0.13=13p^2 ⇒13/100=13p^2 ⇒ p^2 = 1/100 ∴ p=0.1 Option B ...

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Standard XII

Physics

Order of Magnitude

If 0.13÷ p ...

Question

If $0.13 \div p^{2} = 13$ , then $p = ?$

0.01

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Solution

The correct option is A $0.1$
$0.13 \div p^{2} = 13$
$∴ 0.13 \times \frac{1}{p^{2}} = 13$
$\Rightarrow 0.13 = 13 p^{2}$
$\Rightarrow \frac{13}{100} = 13 p^{2}$
$\Rightarrow p^{2} = \frac{1}{100}$
$∴ p = 0.1$
Option $B$ is correct.

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Q. If

p = - 10

, find the value of

p^{2} - 2 p - 100

An analytic balance has uncertainty In measurement equal to $\pm$ 1 mg. Then report the result in terms of percentage if the weight of a compound is
(a) 1 g
(b) 10 g
(c) 100 g

Question 8 (ii)

If p = - 10, find the value of $p^{2} - 2 p - 100$

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If 0.13÷p2=13, then p=?

The correct option is A 0.10.13÷p2=13∴0.13×1p2=13⇒0.13=13p2⇒13100=13p2⇒p2=1100∴p=0.1Option B is correct.

If $0.13 \div p^{2} = 13$ , then $p = ?$

The correct option is A $0.1$
$0.13 \div p^{2} = 13$
$∴ 0.13 \times \frac{1}{p^{2}} = 13$
$\Rightarrow 0.13 = 13 p^{2}$
$\Rightarrow \frac{13}{100} = 13 p^{2}$
$\Rightarrow p^{2} = \frac{1}{100}$
$∴ p = 0.1$
Option $B$ is correct.