Question

# If 0.5 moles of BaCl2 is mixed with 0.2 moles of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is: The corresponding balanced reaction is: 3BaCl2+2Na3PO4→Ba3(PO4)2+6NaCl

A
0.7 mol
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B
0.5 mol
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C
0.2 mol
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D
0.1 mol
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Solution

## The correct option is D 0.1 molThe given balanced reaction is, 3BaCl2+2Na3PO4→Ba3(PO4)2+6NaCl So, from the balanced reaction, 3 mol of BaCl2 reacts with 2 mol of Na3PO4 to give 1 mol of Ba3(PO4)2 The amount of BaCl2 given here is 0.5 mol. ∴The amount of Na3PO4 needed to completely react with 0.5 mol BaCl2 =23×0.5 mol = 0.33 mol But the amount of Na3PO4 given is 0.2 mol. Thus, Na3PO4 is the limiting reagent here. Hence, the maximum number of moles of Ba3(PO4)2 that can be formed: 12×0.2 mol = 0.1 mol

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