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Question

If 0<x<1, then find the value of x1x((sin(cot1x)sec(cot1x))21)12

A
1x1+x
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B
1+x1x
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C
1x21+x2
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D
1+x2
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Solution

The correct option is B 1+x1x
x1x(sin(cot1x)sec(cot1x))21)12=x1x(11+x2×1+x2x)2112=x1x×1x2x2=1+x1x

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