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Question

If 1+2+22+23++21999 is divided by 5, then the remainder is

A
3
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B
5
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C
0
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D
1
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Solution

The correct option is C 0
1+2+22+23+...+21999=1(220001)21=220001=410001=(51)10001= 1000C051000 1000C15999+ 1000C9995+11=5k+11=5k

Which is divisible by 5, so the remainder is 0.

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