Question

If 1 Faraday were to be 60230 coulombs instead of 96500 coulombs, what will be the charge of an electron?
(1 Faraday= total charge on the collection of 1 mole of electrons)

• A. $1\times {10}^{-19}\text{C}$
• B. $1\times {10}^{-18}\text{C}$
• C. $2\times {10}^{-19}\text{C}$
• D. $2\times {10}^{-18}\text{C}$

Answer 1

The correct option is A $1\times {10}^{-19}\text{C}$

One mole of electrons carries 1 Faraday charge
As $6.023\times {10}^{23}$ electrons carry $60230\text{C}$
So,1 electron carries = $\frac{60230}{6.023\times {10}^{23}}\text{C}$
$=1\times {10}^{-19}\text{C}$