If 1- i 1-2 i 1-3 i -1- ni - a - bi- then2-5-10- 1- n 2 is equal toA- a2-b2B- a2-b2C- -a2-bD- -a2-b2

We have 1+i)(1+2i)(1+3i).....(1+ni)=a+ib .....(i) ⇒ (1 i)(1 2i)(1 3i).....(1 ni)=a ib .....(ii) Multiplying (i) and (ii ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Algebra of Complex Numbers

If 1+ i 1+2 i...

Question

If $(1 + i) (1 + 2 i) (1 + 3 i) . . . . . (1 + n i) = a + b i$ , then2.5.10.... $1 + n^{2}$ is equal to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

If (1+i)(1+2i)(1+3i)......(1+ni) = a+ib, then 2.5.10.....(1+ $n^{2}$ ) is equal to

n^{2}

(1 + i) (1 + 2 i) (1 + 3 i) . . . (1 + n i) = a + i b, then 2 \times 5 \times 10 \times . . . . \times (1 + n^{2})

\sqrt{a^{2} + b^{2}}

\sqrt{a^{2} - b^{2}}

a^{2} + b^{2}

a^{2} - b^{2}

a + b

If $(1 + i) (1 + 2 i) (1 + 3 i) . . . . (1_{n} i) = a + i b, then 2 \times 5 \times 10 \times . . . . \times (1 + n^{2}) is equal to$

If (1 + i) (1 + 2i) (1 + 3i) ...... (1+ni) = a + ib, then 2.5.10.17 ...... ( $1 + n^{2}$ ) =

Join BYJU'S Learning Program