Question

# If 10 g of the ice at $$0^o C$$ is mixed with 10 g of water at $$100^oC$$ , then the final temperature of the mixture will be

A
5oC
B
10oC
C
100K
D
0oC

Solution

## The correct option is B $$10^o C$$solution Heat absorbed by ice $$= mL_{f}+ms \triangle T$$ice$$\triangle Q_{absorb} = (10)(80)+(10)(1)(T-0)$$Heat released by water = M8 $$\triangle T_{water}$$ $$\triangle Q$$  release = 10(1)(100-T)Note : $$\triangle T$$  ice is the temperature changein water that has been converted from water.So, $$\triangle Q$$ absorb = $$\triangle Q$$  release$$\Rightarrow 800+10T = 1000-10T$$$$\Rightarrow T = 10^{\circ}C$$Option - B is correct.Physics

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