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Question

If 10 g of the ice at $$ 0^o C $$ is mixed with 10 g of water at $$ 100^oC $$ , then the final temperature of the mixture will be


A
5oC
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B
10oC
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C
100K
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D
0oC
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Solution

The correct option is B $$ 10^o C $$
solution 
Heat absorbed by ice $$ = mL_{f}+ms \triangle T$$ice
$$ \triangle Q_{absorb} = (10)(80)+(10)(1)(T-0)$$
Heat released by water = M8 $$\triangle T_{water}$$ 
$$ \triangle Q$$  release = 10(1)(100-T)
Note : $$ \triangle T$$  ice is the temperature change
in water that has been converted from water.
So, $$ \triangle Q $$ absorb = $$\triangle Q$$  release
$$ \Rightarrow 800+10T = 1000-10T$$
$$ \Rightarrow T = 10^{\circ}C$$
Option - B is correct.

1147313_1166680_ans_32a06d057eed4c35b3382626bb7ac91d.jpg

Physics

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