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If 10% (w/w) aqueous solution of K2CO3  is kept in a container whose volume capacity is 100 L then, mole fraction (xK2CO3) is equal to:
  1. 0.0254
  2. 0.0138
  3. 0.0188
  4. 0.0368


Solution

The correct option is B 0.0138
10 %(w/w) means 10 g of K2CO3 is present in 100 g of solution.
Mass of K2CO3 in 100 g solution = 10 g
Number of moles of K2CO3 in 100 g solution =given massmolar mass=10138=0.07 mol
Weight of solvent (water) in 100 g solution =10010=90 g
Number of moles of water in 100 g solution =9018=5 mol 
Molefraction=moles of K2CO3moles of K2CO3+moles of solvent
Mole fraction of K2CO3=0.07(0.07+5)=0.0138
 

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