Question

If $100$ ml of $1.0$M $NaOH$ solution is diluted to $1$ $d{m}^3$, the molarity of the resulting solution is:

• A. $1.0$M of $NaOH$
• B. $0.1$M of $NaOH$
• C. $10.0$M of $NaOH$
• D. $0.05$M of $NaOH$

Answer 1

Answer: (B)

$0.1$M of $NaOH$

We know that $M_1{V}_1=M_2{V}_2$

Here, $M_1=1.0MNaOH$

$V_1=100mL$

$M_2=?$

$V_2=1d{m}^3=1000c{m}^3=1000mL$

$M_2=\frac{M_1{V}_1}{V_2}=\frac{1\times 100}{1000}=0.1M$