Question

If 146! is divisible by $5^n$, then find the maximum value of n.

• A. 34
• B. 35
• C. 36
• D. 37

Answer 1

The correct option is B 35

The number of 5's in 146! can be got by $\left[\frac{146}{5}\right]+\left[\frac{146}{5^2}\right]+\left[\frac{146}{5^3}\right]=29+5+1=35$