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Question

If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.


Solution

We know that,

For an A.P., an = a + (n − 1) d

a17 = a + (17 − 1) d

a17 = a + 16d

Similarly, a10 = a + 9d

It is given that

a17a10 = 7

(a + 16d) − (a + 9d) = 7

7d = 7

d = 1

Therefore, the common difference is 1.


Mathematics
Math
Standard X

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