If 18,a,(b−3) are in AP, then find the value of (2a−b)
Given 18,a,b−3 are in A.P
Common difference, a−18=(b−3)−a
Now, a−18=b−3−a
⇒2a−b=18−3
∴2a−b=15
If tan2A=cot(A−18∘), then value of A is ((A - 18) & 2A are acute angle)