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Question

If  $$19$$  water tanks can be filled by a pipe in  $$9\dfrac { 1 } { 2 }$$  hrs,then how much time will be taken by the pipe to fill  $$59$$  such water tanks?


Solution

$$\begin{array}{l} Time\, taken\, to\, fill\, 19\, water\, { { tanks } }=9\dfrac { 1 }{ 2 } h=\dfrac { { 19 } }{ 2 }  \\ \therefore \, Time\, \, taken\, \, to\, fill\, 1\, \, water\, \tan  ks=\dfrac { { 19 } }{ 2 } \div 19 \\ \therefore Time\, taken\, \, to\, fill\, \, 59\, \, such\, water\, { { tanks } }=\dfrac { { 19 } }{ 2 } \times \dfrac { 1 }{ { 19 } } \times 59 \\ =\dfrac { { 59 } }{ 2 } h \\ =29\dfrac { 1 }{ 2 } hours \end{array}$$

Hence, this is the answer.

Mathematics

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