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Question

If (2k1,k) is a solution of the equation 10x9xy=12 then find the value of k.

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Solution


as(2k1,k)isasolutionoftheequationhenceitmustsatisfythegivenequationputx=2k1andy=kthen10(2k1)9(2k1)(k)=12or20k109(2k2k)=12

or20k1018k2+9k=12or18K2+29k22=0

18k229k+22=0asitsD=(29)24.18.22=8411584<0

novalueofkisequationssolution


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