Question

If $2x+2(4+3x)<2+3x>2x+\frac{x}{2}$ then $x$ can take which of the following values.

• A. $-3$
• B. $1$
• C. $0$
• D. $-1$

Answer 1

The correct option is A $-3$

Given,

$2x+2(4+3x)<2+3x>2x+\frac{x}{2}$

Solving $1^{st}$ inequality

$2x+8+6x<2+3x$

$5x<-6$

$x<\frac{-6}{5}$

Solving $2^{nd}$ inequality

$2+3x>2x+\frac{x}{2}$

$\frac{x}{2}>-2$

$x>-4$

$x\in (-4,\frac{-6}{5})$

$x$ can take values $-3$

$A$ is correct.