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Question

If 2x+3y=6 and 1x+12y=2 then
(a) x=1, y=23            (b) x=23, y=1            (c) x=1, y=32            (d) x=32, y=1


Solution

The given equations are
2x+3y=6                                                   .....i1x+12y=2                                                 .....ii
Multiplying (ii) by 2 and subtracting it from (ii), we get
3y-1y=6-42y=2y=1
Substituting y = 1 in (ii), we get
1x+12=21x=2-12=32x=23
Hence, the correct answer is option (b).

Mathematics
RS Aggarwal (2018)
Standard X

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