Question

# If then (a)             (b)             (c)             (d)

Solution

## The given equations are Multiplying (ii) by 2 and subtracting it from (ii), we get $\frac{3}{y}-\frac{1}{y}=6-4\phantom{\rule{0ex}{0ex}}⇒\frac{2}{y}=2\phantom{\rule{0ex}{0ex}}⇒y=1$ Substituting y = 1 in (ii), we get $\frac{1}{x}+\frac{1}{2}=2\phantom{\rule{0ex}{0ex}}⇒\frac{1}{x}=2-\frac{1}{2}=\frac{3}{2}\phantom{\rule{0ex}{0ex}}⇒x=\frac{2}{3}$ Hence, the correct answer is option (b).MathematicsRS Aggarwal (2018)Standard X

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