If 3.01 × 10²⁰ molecules are removed from 98 mg H₂SO₄ then find out mass of oxygen in the H₂SO₄ left behind.
यदि 98 mg H₂SO₄ से 3.01 × 10²⁰ अणु निष्कासित किए जाते हैं, तो शेष H₂SO₄ में ऑक्सीजन का द्रव्यमान ज्ञात कीजिए।

Q. From

2 m g

calcium

1.2 \times 10^{19}

atoms are removed. The amount of calcium left is:
(Take

N_{A} = 6 \times 10^{23}

)

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If 3.01×1020 molecules are removed from 98 mg of H2SO4, then number of moles of H2SO4 left are :

The correct option is B 0.5×10−3 molMolar mass H2SO4= 98 g/mol.98 mg H2SO4=98mg1000mg/g×98g/mol=0.001 moles.3.01×1020 molecules of H2SO4=3.01×10206.02×1023=0.0005 moles.Number of moles of H2SO4 remaining =0.001−0.0005=0.0005=0.5×10−3 moles.

If $3.01 \times 10^{20}$ molecules are removed from $98$ mg of $H_{2} S O_{4}$ , then number of moles of $H_{2} S O_{4}$ left are :