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Question

If 3.01×1020 molecules are removed from 98 mg of H2SO4, then the number of moles of H2SO4 left will be :


A
0.1×103
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B
1.66×103
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C
9.95×102
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D
0.5×103
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Solution

The correct option is D 0.5×103
Moles of H2SO4 in 98 mg(0.098 g) of H2SO4
=198×0.098=0.001 mol
Moles of H2SO4 removed =3.01×10206.02×1023
=0.0005 mol
Moles of H2SO4 left =0.0010.0005
                                 =0.0005                                  =0.5×103

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