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Question

If (35i)3 can be expressed in the form a+ib ,then the ordered pair (a,b) is

A
(198,10)
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B
(198,10)
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C
(198,10)
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D
(198,10)
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Solution

The correct option is B (198,10)
We know that (z1z2)3=z31z323z1z2(z1z2).
(35i)3=33(5i)33×3×5i(35i)
=27125i3135i+225i2
=27+125i135i225 [i3=i,i2=1]
=19810i.

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