{ If }-3 and }4 are the roots of the equation }(x+k)}{(x-4)=0, then the value of }k is

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If x= -2 is a root of equation 3x ²+ 7x + p = 0, then find the value of k so that the roots of the equation x²+ k(4x + k - 1) + p=0 are equal.

x^{4} - (k - 1) x^{2} + (2 - k) = 0

k

x^{2} + 2 x + 4 p = 0

x^{2} + p x (1 + 3 k) + 7 (3 + 2 k) = 0

α

β

x^{2} - 2 x + 4 = 0

α^{n} + β^{n} = 2^{k} cos \frac{n π}{3}

k

- 4

x^{2} + p x - 4 = 0

x^{2} + p x + k = 0

k

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