If $3 (x - 3) = 5 (2 x + 1)$ , then the value of $x$ is-

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 2$
$3 (x - 3) = 5 (2 x + 1)$
$\Rightarrow$ $3 x - 9 = 10 x + 5$
$\Rightarrow$ $3 x - 10 x = 5 + 9$
$\Rightarrow$ $- 7 x = 14$
$\Rightarrow$ $- x = \frac{14}{7}$
$\Rightarrow$ $x = - 2$

Suggest Corrections

Similar questions

x

(3 x - 2) = \frac{4}{5} (2 x - 3) + \frac{86}{15}

\frac{1}{3} (x - \frac{1}{2}) + \frac{1}{5} (2 x + \frac{1}{4}) = \frac{3}{4} (x - \frac{1}{12})

\frac{1}{3} (x - \frac{1}{2}) + \frac{1}{5} (2 x + \frac{1}{4}) = \frac{3}{4} (x - \frac{1}{12})

x = 1 + 2^{1 / 3} + 2^{2 / 3}

x^{3} - 3 x^{2} - 3 x - 1

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & 3 x - 1 & - x + 3 2 x + 1 & 2 + x^{2} & x^{3} - 3 x - 3 & x^{2} + 4 & 3 x \end{matrix} ∣ ∣ ∣ ∣ ∣ = a_{0} + a_{1} x + a_{2} x^{2} + . . . + a_{7} x^{7}

a_{0}

Join BYJU'S Learning Program