If $32$ g of $O_{2}$ contains $6.022 \times 10^{23}$ molecules at NTP then, $32$ g of $S$ under the same conditions will contain :

6.022 \times 10^{23} S

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3.011 \times 10^{21} S

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1 \times 10^{23} S

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12.044 \times 10^{23} S

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Solution

The correct option is A $6.022 \times 10^{23} S$
As both, $O_{2}$ and $S$ have same mass so $32$ g of $O_{2}$ contains same number of moles as $32$ g of $S$ .
So, they both have same number of molecules at NTP.
Therefore, $32$ g of $S$ contains $6.022 \times 10^{23}$ atoms.

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Similar questions

If 32 g of $O_{2}$ contains 6.022 $\times 10^{23}$ molecules at NTP then 32 g of S, under the same conditions, will contain,

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

1

g of

^{12} C

contains

6.022 \times 10^{23}

atoms of Carbon.

Q. 1 g of

^{12} C

contains

6.022 \times 10^{23}

atoms of the isotope.

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If 32 g of O2 contains 6.022×1023 molecules at NTP then, 32 g of S under the same conditions will contain :

The correct option is A 6.022×1023SAs both, O2 and S have same mass so 32 g of O2 contains same number of moles as 32 g of S.So, they both have same number of molecules at NTP.Therefore, 32 g of S contains 6.022×1023 atoms.

If $32$ g of $O_{2}$ contains $6.022 \times 10^{23}$ molecules at NTP then, $32$ g of $S$ under the same conditions will contain :

The correct option is A $6.022 \times 10^{23} S$
As both, $O_{2}$ and $S$ have same mass so $32$ g of $O_{2}$ contains same number of moles as $32$ g of $S$ .
So, they both have same number of molecules at NTP.
Therefore, $32$ g of $S$ contains $6.022 \times 10^{23}$ atoms.