If 45 mL of water is added to 250 mL of a 0.75 M $K_{2} S O_{4}$ solution, what will be the molarity of the diluted solution?

0.75 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.85 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.64 M

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.50 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.64 M
$M_{1} V_{1} = M_{2} V_{2} 0.75 \times 250 = M_{2} \times 295 M_{2} = \frac{(0.75 M) (250 m L)}{(295 m L)} = 0.636 M \sim 0.64 M$

Suggest Corrections

Similar questions

K_{2} S O_{4}

The molarity of a solution having 8.4 volume strength of $H_{2} O_{2}$ is:

H C l

Join BYJU'S Learning Program