If 5=2.236 and 10 =3.162 . Then find (10-5) / 2

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\sqrt{5} = 2.236

\sqrt{10} = 3.162, t h e v a l u e o f \frac{\sqrt{10} - \sqrt{5}}{\sqrt{2}}

\sqrt{5} = 2.236

\sqrt{10} = 3.162

\frac{\sqrt{10} - \sqrt{5}}{\sqrt{2}}

\sqrt{5} = 2.236

\sqrt{10} = 3.162

\frac{\sqrt{10} - \sqrt{5}}{\sqrt{2}}

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} + \sqrt{5} - \sqrt{80}}

\sqrt{5} = 2.236 a n d \sqrt{10} = 3.162

Evaluate $\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}$ , it us given that $\sqrt{5} = 2.236$ and $\sqrt{10} = 3.162$

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