If $_{5} B^{11}$ converts into $_{6} C^{11}$ , then the particle emitted in this process will be

electron

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proton

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neutron

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positron

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Solution

The correct option is A electron
$β^{-}$ minus decay produces an electron and electron anti neutrino.
$β^{-}$ decay increases the proton by $1$ and reduces the neutron number by $1$
Hence, mass number remains same but atomic number increase by $1.$

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Similar questions

_{6} C_{11} \to_{5} B^{11} + β^{+} + X, X

_{6} C^{11} \to_{5} B^{11} + β^{+} + \times

_{6} C^{11}

_{5} B^{11}

_{6} C^{11} \to_{5} B^{11} + β + X

_{90} {Th}^{228}

_{83} {Bi}^{212}

α

β

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