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Question

If 5x+7y6z+8=19,3x+4y+8z+5=35 and 6x+3y+12z=22 the find the value of x+y+z74.

A
69
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B
69
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C
59
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D
59
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Solution

The correct option is A 69
Given:
5x+7y6z+8=19,3x+4y+8z+5=35 and 6x+3y+12z7=22
Calculation:
5x+7y6z+8=195x+7y6z=11(1)
3x+4y+8z+5=35
3x+4y+8z=30(2)
6x+3y+12z7=22
6x+3y+12z=29(3)
Adding equations 1.2 and 3 we get,
14x+14y+14z=70
x+y+z=5
x+y+z74
574=69
Required value is 69

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