Question

If 6 g of coke is heated with one mole of $C{O}_2$, then volume of resultant gaseous mixture at STP will be:

• A. $22.4l$
• B. $33.6l$
• C. $44.8l$
• D. $5.6l$

Answer 1

The correct option is B $33.6l$

6g of $C=$ $\frac{6}{12}$ = 0.5 moles
These 0.5 moles of $C$ react with 1 mole of $C{O}_2$
$\therefore$ amount of resultant mixture $=1+0.5=1.5$ moles
Volume of 1.5 moles = $22.4\times 1.5$ = 33.6L