Question

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be

• A. 4 days
• B. 5 days
• C. 6 days
• D. 7 days

Answer 1

The correct option is A

4 days

Let1 man's 1 day's work = x and 1 boy's 1 day's work = y
Then, 6x+8y $=\frac{1}{10}$ and 26x + 48y $=\frac{1}{2}$
Solving these two equations, we get: x = $\frac{1}{100}$ and y = $\frac{1}{200}$
(15 men + 20 boy)'s 1 day's work $=[\frac{15}{100}+\frac{20}{200}]=\frac{1}{4}$
15 men and 20 boys can do the work in 4 days