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Question

If $$60\%$$ of a first order reaction was completed in $$60$$ minute, $$50\%$$ of the same reaction would be completed in approximately?


A
46 minute
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B
60 minute
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C
40 minute
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D
50 minute
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Solution

The correct option is A $$46$$ minute
Its a 1st Order reaction.

$$k = \dfrac{2.303}{60} log \dfrac{100}{40}$$

$$k = 0.015\space {min}^{-1}$$

$$t = \dfrac{2.303}{0.015} log \dfrac{100}{50}$$

$$t = 46\space min$$

Hence, the correct option is $$A$$

Chemistry

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