CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If $$7$$ times the $$7^{th}$$ term of an AP is equal to $$11$$ times its $$11^{th}$$ term, then its $$18^{th}$$ term will be


A
7
loader
B
11
loader
C
18
loader
D
0
loader

Solution

The correct option is C $$0$$
Let first term and common difference be $$a,d$$ respectively.

nth term $$t_{n}= a+(n-1)d $$

$$7^{th}$$ term= $$a + 6d$$
$$11^{th}$$ term= $$a + 10d$$
Given,
$$7$$ times $$7^{th}$$ term=$$11$$ times $$11^{th}$$ term

$$7\times (a+6d)$$=$$11\times(a+10d)$$

$$\Rightarrow 7a + 42d = 11a + 110d$$

$$\Rightarrow 4a + 68d=0$$

$$\Rightarrow a + 17d= 0$$  

Comparing with $$t_{n}= a+(n-1)d $$, we get $$n=18$$
.
The $$18^{th}$$ term is $$0$$.

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image