If 74z5 is a multiple of 3, where z is a single digit number, what might be the values of z?
All of these
We have been given that 74z5 is a multiple of 3.
Therefore according to the divisibility rule of 3, the sum of all the digits should be a multiple of 3.
Also, z is a single digit number.
∴ 7 + 4 + z + 5 = 16 + z should be a multiple of 3.
The first multiple of 3 which is greater than 16 is 18
⇒ 16 + z = 18 ⇒ z = 2
The next multiple of 3 which is greater than 16 is 21
⇒16+z=21⇒z=5
The next multiple of 3 which is greater than 16 is 24
⇒16+z=24⇒z=8
The next multiple of 3 which is greater than 16 is 27
⇒16+z=24⇒z=11
But 11 is a double digit number, therefore, z cannot be 11.
Hence 2, 5 and 8 are the possible answers.