If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes)
(Take: log2=0.30;log2.5=0.40)
[Report tour answer to closest integer]
A
60
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B
60.00
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C
60.0
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Solution
Time for completion of 75% of a 1st order reaction =90min. ∴ Half life, t12=0.5t34 =902=45min
Rate constant, K=0.69345min−1
Time for completion of 60% of the reaction, t=60%=2.303Klog104 =2.303×450.693[1−.06]=60