Question

If $9x^2+8=22x$, then $x=1,\frac{2}{9}$.

• A. Yes
• B. No
• C. Ambiguous
• D. Data insufficient

Answer 1

Answer: (B)

No

Given equation is, $9x^2-22x+8=0$
$9x^2-18x-4x+8=0$
$(9x-4)(x-2)=0$
$\therefore x=\frac{4}{9},2$