Question

If $a>0$, $b>0$ and $a-b>0$, then?

• A. $a<b$
• B. $a+b<0$
• C. $a>b$
• D. $b-a<0$

Answer 1

Answer: (A)

$a<b$

In this case $a$ and $b$ are both positive $(a>0,b>0)$, but $a-b$ is negative, which is only possible when $a<b$