If A={1,2,3}, then the number of equivalence relation containing(1,2) is
1
2
3
8
Explanation for the correct option:
Finding number equivalence relation.
Given,
A={1,2,3}
Relation,
R ={(1,1),(1,2),(1,3),(2,1),(2,2),(2,3),(3,1),(3,2),(3,3)}
R1={(1,1),(2,2),(3,3),(1,2),(2,1)}
R2={(1,1),(2,2),(3,3),(1,2),(2,1),(2,3),(3,2),(1,3),(3,1)}
There is only two containing equivalence relation (1,2)Hence, correct option is (B).
Let A = {1, 2, 3}. Then number of equivalence relations containing (1, 2) is
(A) 1 (B) 2 (C) 3 (D) 4
37. Let A = {1, 2, 3}. Then find the number of equivalence relations containing (1, 2