If $a_{1}, a_{2}, \cdot \cdot \cdot, a_{15}$ are in A.P. and $a_{1} + a_{8} + a_{15} = 15$ , then $a_{2} + a_{3} + a_{8} + a_{13} + a_{14}$ equals

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Solution

The correct option is C
25

$a_{1} + a_{8} + a_{15} = 3 a_{1} + 21 d = 15$
$\Rightarrow a_{1} + 7 d = 5$
Now, $a_{2} + a_{3} + a_{8} + a_{13} + a_{14} = 5 a_{1} + 35 d$
$5 (a_{1} + 7 d) = 5 \times 5 = 25$

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